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CH(3)-underset(CH(3))underset(|)(CH)-CH=...

`CH_(3)-underset(CH_(3))underset(|)(CH)-CH=CH_(2)+HBr to 'A'`
'A' (predominantly) is:

A

`CH_(3)-underset(Br)underset(|)(CH)-underset(CH_(3))underset(|)CH-CH_(3)`

B

`CH_(3)-underset(CH_(3))underset(|)CH-underset(Br)underset(|)CH-CH_(3)`

C

`CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(2)Br`

D

`CH_(3)-underset(CH_(3))underset(|)overset(Br)overset(|)C-CH_(2)CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
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