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Ozone depletion takes place as : 2O(3)...

Ozone depletion takes place as :
`2O_(3)(g)rarr3O_(2)(g)`
Step1: `O_(3)(g)overset(k)hArrO_(2)(g)+O(g)" "`(fast)
Step2 : `O_(3)(g)+[O]overset(k)rarr2O_(2)(g)" "` (slow)
order of the reaction will be :

A

1

B

2

C

3

D

unpredictable

Text Solution

Verified by Experts

The correct Answer is:
A
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Ozone deplection takes place as : 2O_(3)(g)rarr3O_(2)(g) Step1: O_(3)(g)overset(k)hArrO_(2)(g)+O(g)" " (fast) Step2 : O_(3)(g)+[O]overset(k)rarr2O_(2)(g)" " (slow) order of the raction will be :

The depletion of ozone involves the following steps : Step 1 : O_3underset(K_1)overset(K_2)hArrO_2+O (fast) Step 2 : O_3+Ounderset(K)rarr2O_2 (slow) The predicted order of the reaction will be

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Ozone in the earth's atmosphere decomposes according to the equation: 2O_(3)(g) rarr 3O_(2)(g) This reaction is thought to occur via the two-step mechanism: Step 1: O_(3)(g) hArr O_(2)(g) +O(g) Fast, reversible Step 2: O_(3)(g) +O(g) rarr 2O_(2)(g) slow What rate law is consistent with this mechanism?

Decomposition of ozone follows the given mechanism . From the mechanism select the option which is not correct. Step (i) : O_(3) underset(K_(2))overset(K_(1))hArr O_(2)(g) +O(g)" " [Fast] Step (ii): O_(3)(g) +O(g) overset(K_(3))rarr 2O_(2)(g)" " [Slow]

For the first order reaction 2N_(2)O_(5)(g) rarr 4NO_(2)(g) + O_(2)(g)

The mechanism of the reaction 2NO(g)+H_(2)(g)rarrN_(2)(g)+2H_(2)O(g) , is: Step1: 2NO(g)+H_(2)(g)overset(("slow"))rarrN_(2)+H_(2)O_(2) Step2: H_(2)O_(2)+H_(2)overset("fast")rarr2H_(2)O

The rate law for the decompoistion of gaseous N_(2)O_(5) , N_(2)O_(5)(g) rarr 2NO_(2)(g) + (1)/(2)O_(2)(g) is observed to be: r = (-d[N_(2)O_(5)])/(dt) = k[N_(2)O_(5)] A reaction machanism which has been suggested to be conisstent with this rate law is N_(2)O_(5)(g) overset(k_(eq))hArr NO_(2)(g)+NO_(3)(g) ("fast equilibrium") NO_(2) (g) + NO_(3)(g) overset(k_(1))rarr NO_(2)(g) + NO(g) + O_(2)(g) (slow) NO(g) + NO_(3)(g) overset(k_(2))rarr 2NO_(2)(g) (fast)

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