`CH_3-overset(O)overset(||)(C )-OH overset(NH_3)(rarr)(P)overset(Al_2O_3)(rarr)(Q)overset(Br_2//KOH)(rarr)(R )`. R is

Options

A. `CH_3CH_2NH_2`
B. `CH_3CN`
C. `CH_3CH_2COOH`
D. `CH_3NH_2`

Answer

To solve the given question step by step, let's break down the reactions involved:

### Step 1: Reaction of Acetic Acid with Ammonia
The first step involves the reaction of acetic acid (CH₃COOH) with ammonia (NH₃). This reaction leads to the formation of ammonium acetate.

**Reaction:**
\[ \text{CH}_3\text{COOH} + \text{NH}_3 \rightarrow \text{CH}_3\text{COONH}_4^+ \]

**Result:**
The product \( P \) is ammonium acetate, which can be represented as:
\[ P = \text{CH}_3\text{COONH}_4^+ \]

### Step 2: Dehydration of Ammonium Acetate
Next, we heat the ammonium acetate in the presence of \( Al_2O_3 \). This acts as a dehydrating agent, removing water (H₂O) and forming acetamide.

**Reaction:**
\[ \text{CH}_3\text{COONH}_4^+ \xrightarrow{Al_2O_3, \text{heat}} \text{CH}_3\text{CONH}_2 \]

**Result:**
The product \( Q \) is acetamide (ethanamide):
\[ Q = \text{CH}_3\text{CONH}_2 \]

### Step 3: Bromination of Acetamide
In the third step, we treat acetamide with bromine (Br₂) in the presence of potassium hydroxide (KOH). This reaction is known as the Hofmann degradation reaction.

**Reaction:**
\[ \text{CH}_3\text{CONH}_2 + \text{Br}_2 + \text{KOH} \rightarrow \text{CH}_3\text{NH}_2 + \text{CO}_2 + \text{KBr} + \text{H}_2\text{O} \]

**Result:**
The product \( R \) is methylamine (CH₃NH₂) along with carbon dioxide (CO₂) as a byproduct:
\[ R = \text{CH}_3\text{NH}_2 \]

### Final Answer
Thus, the final product \( R \) is:
\[ R = \text{CH}_3\text{NH}_2 \]

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