An inorganic compounds gives off `O_2` on heating. It also makes the colourless solution of potassium iodide to acquire purple tinge. The compound can be

Options

A. `SO_3`
B. `K_2CO_3`
C. `H_2O_2`
D. `H_2O`

Answer

To solve the problem, we need to identify the inorganic compound based on the two key observations provided:

1. The compound gives off \( O_2 \) when heated.
2. It turns a colorless solution of potassium iodide (KI) to a purple tinge.

### Step-by-Step Solution:

**Step 1: Identify the compound that releases \( O_2 \) on heating.**
- One common inorganic compound that releases oxygen gas (\( O_2 \)) upon heating is hydrogen peroxide (\( H_2O_2 \)). When \( H_2O_2 \) is heated, it decomposes as follows:
\[ 2 H_2O_2 \rightarrow 2 H_2O + O_2 \]
- This reaction confirms that the first condition is satisfied.

**Step 2: Analyze the reaction of \( H_2O_2 \) with potassium iodide (KI).**
- When \( H_2O_2 \) is added to a solution of potassium iodide, it reacts to produce iodine (\( I_2 \)):
\[ H_2O_2 + 2 KI \rightarrow 2 KOH + I_2 \]
- The iodine (\( I_2 \)) produced in the solution imparts a purple color. This satisfies the second condition of the problem.

**Step 3: Conclusion**
- Since both conditions are met by hydrogen peroxide (\( H_2O_2 \)), we can conclude that the compound in question is \( H_2O_2 \).

### Final Answer:
The compound can be hydrogen peroxide (\( H_2O_2 \)).

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