Calculate the amount of bromine required to convert 10 g of phenol into 2, 4, 6 - tribromophenol (Report your answer as whole number only)

Answer

To calculate the amount of bromine required to convert 10 g of phenol into 2, 4, 6-tribromophenol, we can follow these steps:

### Step 1: Determine the molecular mass of phenol (C6H5OH)
- The molecular formula of phenol is C6H5OH.
- Calculate the molecular mass:
- Carbon (C): 6 atoms × 12 g/mol = 72 g/mol
- Hydrogen (H): 6 atoms × 1 g/mol = 6 g/mol
- Oxygen (O): 1 atom × 16 g/mol = 16 g/mol
- Total molecular mass of phenol = 72 + 6 + 16 = 94 g/mol

### Step 2: Determine the molecular mass of bromine (Br)
- The molecular mass of bromine (Br) is 80 g/mol.

### Step 3: Determine the stoichiometry of the reaction
- The reaction of phenol with bromine to form 2, 4, 6-tribromophenol involves the addition of 3 moles of bromine:
- C6H5OH + 3 Br2 → C6H2Br3OH + 3 HBr

### Step 4: Calculate the amount of bromine required for 1 g of phenol
- From the stoichiometry, 1 mole of phenol (94 g) requires 3 moles of bromine (3 × 80 g = 240 g).
- Therefore, 1 g of phenol requires:
\[ \text{Bromine required for 1 g of phenol} = \frac{240 \text{ g}}{94 \text{ g}} \approx 2.55 \text{ g} \]

### Step 5: Calculate the amount of bromine required for 10 g of phenol
- For 10 g of phenol, the amount of bromine required is:
\[ \text{Bromine required for 10 g of phenol} = 10 \text{ g} \times 2.55 \text{ g/g} \approx 25.5 \text{ g} \]

### Step 6: Round to the nearest whole number
- The nearest whole number to 25.5 g is 26 g.

### Final Answer
The amount of bromine required to convert 10 g of phenol into 2, 4, 6-tribromophenol is **26 g**.

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