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A ring of mass m free to slide on a fixed smooth horizontal rod is attached to a particle of mass M kg by a inextensible string of length l. Initially, both M and m are at rest and the string is vertical. A horizontal velocity `v_(0)` is imparted to the particle. The maximum height up to which block will rise w.r.t its initial position is (M = 2m)

A

`(v_(0)^(2))/(2g)`

B

`(v_(0)^(2))/(4g)`

C

`(v_(0)^(2))/(6g)`

D

`(v_(0)^(2))/(8g)`

Text Solution

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The correct Answer is:
C
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