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if f(x)=e^(-1/x^2),x!=0 and f (0)=0 th...

if `f(x)=e^(-1/x^2),x!=0` and `f (0)=0` then `f'(0)` is

A

not defined

B

1

C

0

D

2

Text Solution

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The correct Answer is:
C
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