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If the complex number omega=x+iy(AA x, y...

If the complex number `omega=x+iy(AA x, y in R and i^(2)=-1)` satisfy the equation `omega^(3)=8i`, then the maximum vlaue of y is

A

1

B

`(sqrt3)/(2)`

C

`(1)/(2)`

D

2

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The correct Answer is:
To solve the problem, we need to find the maximum value of \( y \) for the complex number \( \omega = x + iy \) that satisfies the equation \( \omega^3 = 8i \). ### Step-by-Step Solution: 1. **Express the equation**: We start with the equation given: \[ \omega^3 = 8i \] where \( \omega = x + iy \). 2. **Expand \( \omega^3 \)**: Using the binomial theorem, we expand \( (x + iy)^3 \): \[ (x + iy)^3 = x^3 + 3x^2(iy) + 3x(iy)^2 + (iy)^3 \] This simplifies to: \[ = x^3 + 3x^2(iy) + 3x(i^2y^2) + i^3y^3 \] Knowing that \( i^2 = -1 \) and \( i^3 = -i \), we have: \[ = x^3 + 3x^2(iy) - 3xy^2 - iy^3 \] Rearranging gives: \[ = (x^3 - 3xy^2) + i(3x^2y - y^3) \] 3. **Set equal to \( 8i \)**: Now, we equate the real and imaginary parts to those of \( 8i \): \[ x^3 - 3xy^2 = 0 \quad \text{(real part)} \] \[ 3x^2y - y^3 = 8 \quad \text{(imaginary part)} \] 4. **Solve the real part equation**: From the real part equation: \[ x^3 = 3xy^2 \] If \( x \neq 0 \), we can divide both sides by \( x \): \[ x^2 = 3y \quad \Rightarrow \quad x = \sqrt{3y} \quad \text{or} \quad x = -\sqrt{3y} \] 5. **Substitute into the imaginary part**: We substitute \( x^2 = 3y \) into the imaginary part equation: \[ 3(3y)y - y^3 = 8 \] This simplifies to: \[ 9y^2 - y^3 = 8 \] Rearranging gives: \[ y^3 - 9y^2 + 8 = 0 \] 6. **Find the roots of the polynomial**: We can use the Rational Root Theorem or synthetic division to find the roots of the polynomial. Testing \( y = 1 \): \[ 1^3 - 9(1^2) + 8 = 1 - 9 + 8 = 0 \] So \( y = 1 \) is a root. We can factor the polynomial as: \[ (y - 1)(y^2 - 8y - 8) = 0 \] 7. **Solve the quadratic**: Now we solve \( y^2 - 8y - 8 = 0 \) using the quadratic formula: \[ y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{8 \pm \sqrt{64 + 32}}{2} = \frac{8 \pm \sqrt{96}}{2} = \frac{8 \pm 4\sqrt{6}}{2} = 4 \pm 2\sqrt{6} \] 8. **Determine the maximum value of \( y \)**: The values of \( y \) are \( 1 \), \( 4 + 2\sqrt{6} \), and \( 4 - 2\sqrt{6} \). The maximum value among these is: \[ 4 + 2\sqrt{6} \] However, we need to check if this value is valid in the context of the original equations. Since \( 2\sqrt{6} \approx 4.899 \), we find that \( 4 + 2\sqrt{6} \) is greater than \( 1 \). 9. **Conclusion**: The maximum value of \( y \) that satisfies the equation \( \omega^3 = 8i \) is: \[ \boxed{1} \]
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