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The orthocentre of the triangle whose ve...

The orthocentre of the triangle whose vertices are `(1, 1), (5, 1) and (4, 5)` is

A

`((9)/(4), -(1)/(3))`

B

`(4, 13)`

C

`(4, (9)/(4))`

D

`(4, (7)/(4))`

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The correct Answer is:
To find the orthocenter of the triangle with vertices \( A(1, 1) \), \( B(5, 1) \), and \( C(4, 5) \), we will follow these steps: ### Step 1: Find the slopes of the sides of the triangle 1. **Calculate the slope of side \( AB \)**: \[ \text{slope of } AB = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 1}{5 - 1} = 0 \] The slope of line \( AB \) is \( 0 \) (horizontal line). 2. **Calculate the slope of side \( BC \)**: \[ \text{slope of } BC = \frac{5 - 1}{4 - 5} = \frac{4}{-1} = -4 \] 3. **Calculate the slope of side \( CA \)**: \[ \text{slope of } CA = \frac{5 - 1}{4 - 1} = \frac{4}{3} \] ### Step 2: Find the slopes of the altitudes 1. **The slope of the altitude from vertex \( C \) to side \( AB \)**: Since \( AB \) is horizontal (slope = 0), the altitude from \( C \) will be vertical. Therefore, its slope is undefined (or we can say it is vertical). 2. **The slope of the altitude from vertex \( A \) to side \( BC \)**: The slope of \( BC \) is \( -4 \). The slope of the altitude from \( A \) will be the negative reciprocal: \[ \text{slope of altitude from } A = \frac{1}{4} \] ### Step 3: Find the equations of the altitudes 1. **Equation of the altitude from \( C(4, 5) \)**: Since it is vertical, the equation is: \[ x = 4 \] 2. **Equation of the altitude from \( A(1, 1) \)**: Using the point-slope form \( y - y_1 = m(x - x_1) \): \[ y - 1 = \frac{1}{4}(x - 1) \] Simplifying: \[ 4y - 4 = x - 1 \implies x - 4y + 3 = 0 \] ### Step 4: Find the intersection of the two altitudes To find the orthocenter, we solve the equations: 1. From the vertical line \( x = 4 \). 2. Substitute \( x = 4 \) into the equation \( x - 4y + 3 = 0 \): \[ 4 - 4y + 3 = 0 \implies 4y = 7 \implies y = \frac{7}{4} \] ### Conclusion The orthocenter of the triangle is: \[ \text{Orthocenter} = \left(4, \frac{7}{4}\right) \] ### Final Answer The orthocenter of the triangle is \( \left(4, \frac{7}{4}\right) \). ---
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