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A balloon is rising vertically upwards. An an instant, an observation on the ground, whose distance from the balloon is 100 meters, sees the balloon at an angle of elevation of `30^(@)`. If the balloon rises further vertically to a point where the angle of elevation as seen by the observer is `45^(@)`, then its height (in meters) from the ground is
`("Take "sqrt3=1.73)`

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To solve the problem, we will break it down step by step. ### Step 1: Understanding the situation We have an observer on the ground who sees a balloon at an angle of elevation of \(30^\circ\) when it is 100 meters away horizontally. We need to find the height of the balloon when the angle of elevation changes to \(45^\circ\). ### Step 2: Setting up the first triangle Let’s denote: - The height of the balloon at the first observation as \(h_1\). - The horizontal distance from the observer to the balloon as \(d = 100\) meters. Using the angle of elevation \(30^\circ\): \[ \tan(30^\circ) = \frac{h_1}{d} \] Since \(\tan(30^\circ) = \frac{1}{\sqrt{3}}\), we can write: \[ \frac{1}{\sqrt{3}} = \frac{h_1}{100} \] Thus, \[ h_1 = \frac{100}{\sqrt{3}} = \frac{100 \times 1.73}{3} \approx 57.67 \text{ meters} \] ### Step 3: Setting up the second triangle Now, when the balloon rises further, the angle of elevation becomes \(45^\circ\). Let the new height of the balloon be \(h_2\). Using the angle of elevation \(45^\circ\): \[ \tan(45^\circ) = \frac{h_2}{d} \] Since \(\tan(45^\circ) = 1\), we have: \[ 1 = \frac{h_2}{100} \] Thus, \[ h_2 = 100 \text{ meters} \] ### Step 4: Finding the total height from the ground Now, we need to find the total height of the balloon from the ground when it is at the \(45^\circ\) angle of elevation. The height of the balloon when it was first observed was \(h_1 \approx 57.67\) meters. The balloon has risen from this height to \(h_2 = 100\) meters. ### Step 5: Conclusion The total height of the balloon from the ground when the angle of elevation is \(45^\circ\) is: \[ h_2 = 100 \text{ meters} \] ### Final Answer The height of the balloon from the ground is **100 meters**. ---
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