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A particle of mass 0.5 kg is displaced f...

A particle of mass `0.5 kg` is displaced from position `vec r_(1)(2,3,1)` to`vec r_(2)(4,3,2)` by applying a force of magnitude `30 N` which is acting along `(hati + hatj + hatk)`. The work done by the force is

A

`10 sqrt 3 J`

B

`30 sqrt 3 J`

C

`30 J`

D

`40 J`

Text Solution

Verified by Experts

The correct Answer is:
`(2)`
`F_(x) = F cos alpha, F_(y) = F cos Beta, F_(2) = F cos gamma, W = F.S`
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NARAYNA-WORK , ENERGY & POWER -EXERCISE -II (H.W)
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