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Kinetic energy of a particle moving in a...

Kinetic energy of a particle moving in a straight line varies with time `t` as `K = 4t^(2)`. The force acting on the particle

A

is constant

B

is increasing

C

is decreasing

D

first increases and then decreases

Text Solution

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The correct Answer is:
`(1)`
`1/2 mv^(2) = 4t^(2),` `therefore v = (sqrt(8/(m)))t` compairing with v = at, a = constant i.e, the force acting on the particle is constant
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