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A vertically projected body attains the ...

A vertically projected body attains the maximum height in `6s`. The ratio of kinetic energy at the end of `3^(rd)` second to decrease in kinetic energy in the next three seconds is

A

`1 : 1`

B

`1 : 3`

C

`3 : 1`

D

`9 : 1`

Text Solution

Verified by Experts

The correct Answer is:
`(1)`

`t_(a) = u /g = 6 Rightarrow u = 6g`
`KE : Delta KE = 1/2m(u - gt)^(2): (1/2m(u - gt)^(2) - 0)`
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NARAYNA-WORK , ENERGY & POWER -EXERCISE -II (H.W)
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  2. n' identical cubes each of mass 'm' and edge 'L' are on a floor. If th...

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  3. A vertically projected body attains the maximum height in 6s. The rati...

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  4. The kinetic energy K of a particle moving along a circle of radius R d...

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  5. A uniform chain of mass m and length l is placed on a smooth table so ...

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  6. These diagrams represent the potential energy U of a diatomic molecule...

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  7. The potential energy of a particle of mass 5 kg moving in the x-y plan...

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  8. A particle of mass m1 is moving with a velocity v(1) and another parti...

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  12. A bullet of mass 10 gm is fired horizontally with a velocity 1000 ms^(...

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  13. A block of mass 5 kg is initially at rest on a rough horizontal surfac...

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  14. A block of mass m = 25 kg on a smooth horizontal surface with a veloci...

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  15. A body freely falls from a certain height onto the ground in a time 't...

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  16. The potential energy function for the force between two atoms in a dia...

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  17. The variation of potential energy U of a body moving along x - axis va...

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  18. The PE of a 2 kg particle, free to move along x-axis is given by V(x)=...

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  19. Figure given below shows the variation of potential energy function U(...

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