A particle of mass m1 is moving with a velocity `v_(1)` and another particle of mass `m_(2)` is moving with a velocity v2. Both of them have the same momentum but their different kinetic energies are E1 and E2 respectively. If `m_(1) gt m_(2)` then

Options

A. `E_(1) lt E_(2)`
B. `E_(1)/E_(2) = m_(1)/m_(2)`
C. `E_(1) gt E_(2)`
D. `E_(1) = E_(2)`

Answer

`(1)`

Explanation

Kinetic energy = `(p^(2))/(2m)
` For same p, E infty 1/m`
`therefore` `(E_(1))/(E_(2)) = (m_(2))/(m_(1)) `
`Asm_(1) gt m_(2)`
So, `E_(1) lt E_(2)`