A freely falling body takes `4s` to reach the ground. One second after release, the percentage of its potential energy, that is still retained is

Options

A. `6.25%`
B. `25%`
C. `37.5%`
D. `93.75%`

Answer

`(4)`

Explanation

Height of fall, `H_(1) = 1/2 G xx 4^(2) = 8g`
After one second, body is at a height of
`H_(2) = 8g - 1/2 g xx 1^(2) = 15g/2`
of P.E retained = `(H_(2))/(H_(1)) xx 100%`