A body is thrown vertically upward from a point `A` 125 m above the ground. It goes up to a maximum height of 250 m above the ground and passes through `A` on its downward journey. The velocity of the body when it is at a height of 70 m above the ground is `(g=10 m//s^(2))`

Options

A. ` 50 ms^(-1)`
B. `60 ms^(-1)`
C. `80 ms^(-1)`
D. `20 ms^(-1)`

Answer

`(2)`

Explanation

`v_(A) = sqrt2gh here h = 125 m ` Velocity at a distance 55m below .A. is
`v^(2) = v_(A)^(2) + 2gh_(1) here h_(1) = 55m`