A train of weight `10^(7)N` is running on a travel track with uniform speed of `36 km h^(-1)`. The frictional force is 0.5 kg f per quintal. If `g = 10 ms^(-2)`, power of engine is

Options

A. `0.5 kW`
B. `5 kW`
C. `50kW`
D. `500 kW`

Answer

`(4)`

Explanation

P= FV
Here `F = 0.5 xx 10^(4) xx 10 = 5 xx 10^(4)`
`V = 36 xx 5/18 = 10 m/s`
`therefore P = 5 xx 10^(4) xx 10 = 5 xx 10^(5) W Rightarrow 500 KW`