The length of a simple pendulum is `1 m`. The bob is given a velocity `7 ms^(-1)` in horizontal direction from mean position. During upward motion of bob, if the string breaks when the bob is horizontal, then the maximum vertical height of ascent of bob from rest position is

Options

A. `2.5 m`
B. `2 m`
C. `3 m`
D. `3.5 m`

Answer

`(1)`

Explanation

since `R_(1) = mg + (mv^(2))/r` and `R_(2) = mg -(mv^(2))/r` If v is velocity when the string is horizontal `7^(2) - v^(2) = 2gL hence H = (v^(2))/2g+ L`