A mass of 2.9 kg is suspended from a string of length 50 cm and is at rest. Another body of mass 100 g, which is moving horizontally with a velocity of `150 m//s` strikes and sticks to it. Subsequently when the string makes an angle of `60^@` with the vertical, the tension in the string is (g = `10 m//s^(2)`)

Options

A. 140 N
B. 135 N
C. 125 N
D. 90 N

Answer

`(2)`

Explanation

`v_(common) = (mu)/(M+m) and T = mg cos theta +(mv)^(2)/r Where v = sqrt(v_("bottom")^(2) - 2 gr(1- cos theta)`