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A body of mass 1 kg is thrown upwards wi...

A body of mass 1 kg is thrown upwards with a velocity `20 ms^(-1)`. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction ? (Take `g = 10 ms^(-2)`)

A

`30 J`

B

`40 J`

C

`10 J`

D

`20 J`

Text Solution

Verified by Experts

The correct Answer is:
`(4)`
Loss of energy = Initial K.E - Final P.E. = 1/2 mv^(2) - mgh = 1/2 xx 1 xx(20)^(2) - 1 xx10 xx 18`
`200-180 = 20 J`
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