A uniform force of `(3 hat(i)+hat(j))` newton acts on a particle of mass `2 kg`. Hence the particle is displaced from position `(2 hat(i)+hat(k))` meter to position `(4 hat(i)+ 3hat(j)-hat(k))` meter. The work done by the force on the particle is `:`

Options

A. `6 J`
B. `13 J`
C. `15 J`
D. `9 J`

Answer

`(4)`

Explanation

`Vec F = (3 hat i + hat j)N `
because displacement =` Delta vec r`
= `vec r_(2) - vec r_(1)` = ( 4 hat i + 3 hat j - hat k) -(2 hat i + hat k)`
`therefore w = vecF.Delta vec r = (6 + 3)J = 9J`