A particle of mass 10 g moves along a circle of radius 64 cm with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to `8xx10^(-4)J` by the end of the second revolution after the beginning of the motion ?

Options

A. `0.2 m/s^(2)`
B. `0.1 m/s^(2)`
C. `0.15 m/s^(2)`
D. `0.18 m/s^(2)`

Answer

`(2)`

Explanation

`W_("all") = KE(uparrow)`
` (ma_(t))(s) = 1/2 (mv^(2))`
`(10 xx 10^(-3))(a_(t))(4pi xx6.4 xx 10^(-2)) = 8 xx 10^(-4)`
`Rightarrow a_(t) = 0.1 m/s^(2)`