Solve `log_4 (8)+log_4 (x+3)-log_4 (x-1)=2`

Explanation

`log_(4)^(8)+log_(4)(x+3)-log_(4)(x-1)=2`
`or"log"_(4) (8(x+3))/(x-1)=2`
or `(8(x+3))/(x-1)=4^(2)`
`orx+3=2x-2`
`rArr" "x=5`
Also for x=5 all terms of the equation are defined.