Solve : `6((log)_x2-(log)_4x)+7=0.`

Explanation

`6(log_(x)2-log_(4)x)+7=0`
`or(6log_(x)2-(1)/(2)log_(2)x)+7=0`
`or6((1)/(y)-(y)/(2))+7=0` (where y = `log_(2)x)`
`or6((2-y^(2))/(2y))+7=0`
`or3((2-y^(2))/(y))+7=0`
`or6-3y^(2)+7y=0`
`or3y^(2)-7y=0`
`or3y^(2)+2y-9-6=0`
`or3y^(2)+2y-9y-6=0`
`or(y-3)(3y+2)=0`
`ory=3ory=-2//3`
`rArrlog_(2)x=3or-2//3`
`or=8orx=2^(2//3)`