Solve ` log_(2)|x-1| lt 1`.

Explanation

` log_(2)|x-1|lt 1`
` rArr 0 lt |x-1| lt 2^(1)`
` rArr -2 lt x-1 lt 2 and x - 1 ne 0`
`rArr -1 lt x lt 3 and x ne 1`
` rArr x in (-1, 3) - {1}`