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Solve (log)(0. 2)|x-3|geq0....

Solve `(log)_(0. 2)|x-3|geq0.`

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` log_(0.2)|x-3| ge 0`
` rArr 0 lt |x-3| le (0.2)^(0)`
` rArr 0 le |x-3| le 1`
` rArr -1 le x-3 le 1 and x-3 ne 0`
` rArr 2 le x le 4 and x ne 3`
` rArr x in [2, 4] - {3}`
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