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Evaluate (72.3)^(1/3); if log 0.723=bar(...

Evaluate `(72.3)^(1/3); if `log 0.723=bar(1).8591`

Text Solution

Verified by Experts

Let `root(3)72.3`. Then
` log x = log(72.3)^(1//3)`
` or log x = 1/3 log 72.3`
` or log x = 1/3 xx 1.8591`
` rArr log x = 0.6197`
` or x = "antilog "` (0.6197)`
` = 4.166 ` (using antilog table)
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