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Solve for x: log(4) log(3) log(2) x = 0....

Solve for `x: log_(4) log_(3) log_(2) x = 0`.

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To solve the equation \( \log_{4} \log_{3} \log_{2} x = 0 \), we will follow these steps: ### Step 1: Rewrite the equation We start with the equation: \[ \log_{4} \log_{3} \log_{2} x = 0 \] ### Step 2: Apply the property of logarithms Using the property of logarithms, we know that if \( \log_{b} a = 0 \), then \( a = 1 \). Therefore, we can rewrite our equation as: \[ \log_{3} \log_{2} x = 1 \] ### Step 3: Solve for \( \log_{3} \log_{2} x \) Now, we apply the same property again: \[ \log_{2} x = 3^{1} = 3 \] ### Step 4: Solve for \( \log_{2} x \) Next, we solve for \( x \) using the property of logarithms again: \[ x = 2^{3} = 8 \] ### Final Answer Thus, the solution for \( x \) is: \[ \boxed{8} \]

To solve the equation \( \log_{4} \log_{3} \log_{2} x = 0 \), we will follow these steps: ### Step 1: Rewrite the equation We start with the equation: \[ \log_{4} \log_{3} \log_{2} x = 0 \] ...
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