The line `(x-2)/3=(y+1)/2=(z-1)/1` intersects the curve `x y=c^(I2),z=0` if `c` is equal to a. `+-1` b. `+-1//3` c. `+-sqrt(5)` d. none of these

Options

A. `ne1`
B. `+-1//3`
C. `+-sqrt5`
D. none of these

Answer

c

Explanation

We have z=0 for the point, where the line intersects the curve. Therefore,
`(x-2)/(3)=(y+1)/(2)=(0-1)/(-1)`
`implies(x-2)/(3)=1and(y+1)/(2)=1`
`impliesx=5andy=1`
Putting these valese in `xy=c^(2)` we get
`5=c^(2)orc=+-sqrt5`