Home
Class 12
MATHS
Let L be the line of intersection of ...

Let L be the line of intersection of the planes `2x""+""3y""+""z""=""1` and `x""+""3y""+""2z""=""2` . If L makes an angles ` alpha `with the positive x-axis, then cos` alpha ` equals `1/(sqrt(3))` `1/2` 1 `1/(sqrt(2))`

A

`(1)/(2)`

B

1

C

`(1)/(sqrt2)`

D

`(1)/(sqrt3)`

Text Solution

Verified by Experts

The correct Answer is:
d

Since line of intersection is perpendicular to both the planes, direction rations of the line of intersection is ltbgt `|[hati,hatj,hatk],[2,3,1],[1,3,2]|=3hati-3hatj+3hatk`
Hence, `cosalpha=(3)/(sqrt(9+9+9))=(1)/(sqrt3)`
Promotional Banner

Topper's Solved these Questions

  • THREE-DIMENSIONAL GEOMETRY

    CENGAGE|Exercise Exercise (Multiple)|17 Videos
  • THREE-DIMENSIONAL GEOMETRY

    CENGAGE|Exercise Exercise (Reasoning Questions)|10 Videos
  • THREE-DIMENSIONAL GEOMETRY

    CENGAGE|Exercise Exercise (Subjective)|16 Videos
  • THREE DIMENSIONAL GEOMETRY

    CENGAGE|Exercise Question Bank|20 Videos
  • TRIGNOMETRIC RATIOS IDENTITIES AND TRIGNOMETRIC EQUATIONS

    CENGAGE|Exercise Question Bank|34 Videos

Similar Questions

Explore conceptually related problems

Let L be the line of intersection of the planes 2x+3y+z=1 and x+3y+2z=2. If L makes an angle alpha with the positive x-axis,then cos alpha equals a.(1)/(2) b.1 c.(1)/(sqrt(2)) d.(1)/(sqrt(3))

Let L.be the line of intersection of the planes 2x+3y+z=1 and x+3y+2z=2. If L makes an angles alphawith the positive x-axis, then cos alpha equals

Let L be the line of intersection of the planes 2x+3y+z=1 and x+3y+2z=2 . If L makes an angle alpha with the positive X=axis, then cosalpha equals

The Plane 2x - 3y + 6z - 11 = 0 makes an angle sin^(-1) (alpha) with x-axis. The value of alpha is equal to

The equation of a plane passing through the line of intersection of the planes x+2y+3z=2 and x-y+z=3 and at a distance (2)/(sqrt(3)) from the point (3,1,-1) is

The plane 2x-3y+6z-11=0 makes an angle sin^(-1)(alpha) with X-axis. The value of alpah is

CENGAGE-THREE-DIMENSIONAL GEOMETRY -Exercise (Single)
  1. then image of the point (-1,3,4) in the plane x-2y=0

    Text Solution

    |

  2. The perpendicular distance between the line vecr = 2hati-2hatj+3hatk+l...

    Text Solution

    |

  3. Let L be the line of intersection of the planes 2x""+""3y""+""z""="...

    Text Solution

    |

  4. The length of the perpendicular drawn from (1,2,3) to the line (x-6...

    Text Solution

    |

  5. If the angle theta between the line (x+1)/1=(y-1)/2=(z-2)/2 and the pl...

    Text Solution

    |

  6. The intersection of the spheres x^2+y^2+z^2+7x-2y-z=13a n dx^2+y^2=...

    Text Solution

    |

  7. If a plane cuts off intercepts OA = a, OB = b, OC = c from the coordi...

    Text Solution

    |

  8. A line makes an angel theta with each of the x-and z-axes. If the a...

    Text Solution

    |

  9. The shortest distance from the plane 12 x+y+3z=327to the sphere x^2+y^...

    Text Solution

    |

  10. A tetrahedron has vertices O(0,0,0),A(1,2,1),B(2,1,3),a n dC(-1,1,2), ...

    Text Solution

    |

  11. The radius of the circle in which the sphere x^(I2)+y^2+z^2+2z-2y-4z...

    Text Solution

    |

  12. The lines (x-2)/1=(y-3)/2=(z-4)/(-k)a n d=(x-1)/k=(y-4)/2=(z-5)/1 are ...

    Text Solution

    |

  13. The point of intersection of the lines (x-5)/3=(y-7)/(-1)=(z+2)/1a ...

    Text Solution

    |

  14. Two system of rectangular axes have the same origin. IF a plane cuts t...

    Text Solution

    |

  15. Find the equation of a plane which passes through the point (3, 2, 0...

    Text Solution

    |

  16. The dr. of normal to the plane through (1,0,0), (0,1,0) which makes an...

    Text Solution

    |

  17. The centre of the circle given by vecr.(hati+2hatj+2hatk)=15and|vecr-(...

    Text Solution

    |

  18. The lines which intersect the skew lines y=m x ,z=c ; y=-m x ,z=-c ...

    Text Solution

    |

  19. Distance of the point P(vecc) from the line vecr=veca+lamdavecb is

    Text Solution

    |

  20. From the point P(a ,b ,c), let perpendicualars P La n dP M be drawn to...

    Text Solution

    |