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(cos9x-cos5x)/(sin17x-sin3x)=-(sin2x)/(c...

`(cos9x-cos5x)/(sin17x-sin3x)=-(sin2x)/(cos10x)`

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To solve the equation \((\cos 9x - \cos 5x) / (\sin 17x - \sin 3x) = -(\sin 2x / \cos 10x)\), we will use trigonometric identities to simplify both sides of the equation. ### Step-by-Step Solution: 1. **Use the Cosine Difference Identity**: The identity for the difference of cosines is: \[ \cos A - \cos B = -2 \sin\left(\frac{A + B}{2}\right) \sin\left(\frac{A - B}{2}\right) ...
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