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cotxcot2x-cot2xcot3x-cot3xcotx=1...

`cotxcot2x-cot2xcot3x-cot3xcotx=1`

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To solve the equation \( \cot x \cot 2x - \cot 2x \cot 3x - \cot 3x \cot x = 1 \), we can follow these steps: ### Step 1: Rewrite \( \cot 3x \) Using the cotangent addition formula, we know that: \[ \cot(3x) = \cot(2x + x) = \frac{\cot 2x \cot x - 1}{\cot 2x + \cot x} \] ...
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