In Fraunhofer diffraction experiment, the first minima of red light (`lambda` = 660 nm ) is formed on the first maxima of another light of wavelength `lambda'`. Find the value of `lambda'`.

In Fraunhofer diffraction experiment, the first minima of red light (lambda = 600 nm ) if formed on the first maxima of another light of wavelength lambda' . Find the value of lambda' .

In Fraundhofer diffraction experiment the first minima of red light (lambda=660mm) is formed on the first maxima of another light of wavelength lambda . Find the value of lambda .

In a single slit Fraunhofer diffraction experiment, the wavelength of the light used is 400 mm and the first minimum is obtained for diffraction angle 30^(@) . The magnitude of theta for first secondary maximum is

In an ideal double slit experiment when a glass plate having refractive index 1.5 and thickness t is placed in the path of interfered light rays of wavelength lambda then the intensity remains unchanged at the place where the central maximum was previously formed. Then the minimum thickness of the glass plate is

The angular width of central maximum of a Fraunhofer diffraction fringe formed by a narrow slit is measured. For this, the slit is illuminated by a light of wavelength 6000 Å. When the slit is illuminated by light of another wavelength, it is found that the angular width decreases by 30%. Find the wavelength of the light used in the second case. Now, in the first case, the total set-up of the experiment is immersed in a liquid. It is found that, the angular width of central maximum decreases by same amount. Calculate the refractive index of the liquid.

In a diffraction experiment with waves of wavelength lambda , if the slit width is small enough there will be no intensity minima i.e., no dark fringes. What is the maximum slit width for which this occurs? Explain your answer.

Three points (0,0), (3,sqrt3),(3,lambda) form an equilateral triangle. Then find the value of lambda .

When a certain metalic surface is illuminated with monochromatic light of wavelength lamda the stopping potential is V_0 When the same surface is illuminated with light of wavelength 2lambda , the stopping potential frac(V_0)(4) ./ If the velocity of light in air is C, then find threshold frequency. Write down de Brogile hypotesis.

In a single slit experiment, angular width of the first minimum obtained by using the light of wavelength 6980 Å is 2^(@) . The width of the slit is