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If alpha=F/v^(2) sin beta t, find dimens...

If `alpha=F/v^(2) sin beta t`, find dimensions of `alpha` and `beta`. Here v=velocity, F= force and t= time.

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Here `sin betat` and `beta t` must be dimensionless
So `[beta t]=1rArr[beta]=[(1)/(t)]=[T^(-1)]_(,)[alpha]=[(F)/(v^(2))sin beta t]=[(F)/(v^(2))]=[(MLT^(2))/(L^(2)T^(2))]=[ML^(-1)]`
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