A particle is moving along a straight line OX, At a time t (in seconds) the distance x (in metres) of particle from point O is given by `x=10+6t-3t^(2)`. How long would the particle travel before coming to rest?

Explanation

Initial value of x, at t=0, `x_(1)=10m`
Velocity `v=(dx)/(dt)`=6-6t When v=0, t=1s
Final value of `x, at t=1s`, `x_(2)=10+6xx1-3(1^(2))`=13m
Distance travelled `=x_(2)-x_(1)=13-10=3m`