In a straight line motion the distance travelled is proportional to the square root of the time taken The acceleration of the particle is proportional to :-

Options

A. velocity
B. `v^(2)`
C. `v^(3)`
D. `sqrt(V)`

Answer

C

Explanation

`s prop sqrt(t)`
`s=kt^(1//2)`
`v=(ds)/(dt)=(k)/(2)(d)/(dt)(t^(-1//2))=(k)/(2)(-(1)/(2))t^(-3//2)=-(k)/(4)t^(-3//2)`
`a prop 1^(-3//2)rArr aprop(t^(-1//2))rArra prop v^(3)`