A particle travels 10m in first 5 sec and 10 m in next 3 sec. Assuming constant acceleration what is the distance travelled in next 2 sec.

Options

A. 8.3 m
B. 9.3 m
C. 10.3 m
D. None of these

Answer

A

Explanation

For first '5' sec.
`10=uxx5+(1)/(2)axx5^(2)`
`4=2u+5a`....(1)
`20=uxx8+(1)/(2) axx8^(2)`
`5=2u+8a` ....(2)
solving equation (1) and (2)
`u=(7)/(6)m//s, a=(1)/(3)m//s^(2)`
`S_("Next" 2s)=S_(10)-S_(8)`
`=((7)/(6)xx10+(1)/(2)xx(1)/(3)xx10^(2))-(10+10)`
`=8.3 m`