A stone is thrown vertically upwards. When stone is at a height half of its maximum height, its speed is `10 ms^-1` , then the maximum height attained by the stone is (`g= 10 ms^(-2)`)

Options

A. 8m
B. 20m
C. 10m
D. 16m

Answer

C

Explanation

`v^(2)=u^(2)-2g(h)/(2)`
`0=(10)^(2)-10h`
`h=10m`