When a ball is thrown up vertically with velocity `v_0`, it reaches a maximum height of h. If one wishes to triple the maximum height then the ball should be thrown with velocity

Options

A. `sqrt(3) v_(0)`
B. `3v_(0)`
C. `9 v_(0)`
D. `3//2v_(0)`

Answer

A

Explanation

`(h_(2))/(h_(1))=((u_(2)^(2))/(2g))/((u_(1)^(2))/(2g))rArr (3h_(1))/(h_(1))=(u_(2)^(2))/(v_(0))`
`u_(2)^(2)=3v_(0)^(2)rArru_(2)=sqrt(3)v_(0)`