A particle move a distance `x` in time `t` according to equation `x = (t + 5)^-1`. The acceleration of particle is alphaortional to.

Options

A. `("velocity")^(2//3)`
B. `("velocity")^(3//2)`
C. `("distance")^(2)`
D. `("distance")^(-2)`

Answer

B

Explanation

`x=(t+5)^(-1)`
`v=(dx)/(dt)=(-1)(t+5)^(-2)`
`vprop(t_5)^(-2)rArr v^(1//2)prop(t+5)^(-1)`
`a=(dv)/(dt)=(d)/(dt)[-(t+5)^(-2)]=(-1)(-2)(t-5)^(-3)`
`=2[(t+5)^(-1)]^(3)=2(v^(1//2))^(3) therefore" aprox "v^(3//2)`