A particle covers half of its total distance with speed `v_1` and the rest half distance with speed `v_2`. Its average speed during the complete journey is.

Options

A. `(v_(1)+v_(2))/(2)`
B. `(v_(1)v_(2))/(v_(1)+v_(2))`
C. `(2v_(1)v_(2))/(v_(1)+v_(2))`
D. `(v_(10^(2)v_(2)^(2))/(v_(1)^(2)+v_(2)^(2)))`

Answer

C

Explanation

Average speed
`=("Total distance")/("Time taken")=(s)/((s//2)/(v_(1))+(s//2)/(v_(2)))=(2v_(1)v_(2))/(v_(1)+v_(2))`