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The motion of a particle along a straigh...

The motion of a particle along a straight line is described by equation : `x = 8 + 12 t - t^3` where `x` is in metre and `t` in second. The retardation of the particle when its velocity becomes zero is.

A

`6ms^(-2)`

B

`12ms^(-2)`

C

`24ms^(-2)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
`v=(dx)/(dt)=0+12-3t^(2)=0 rArr t=2s`
At t=2s.
Retardation `=-(dv)/(dt)=-(-6t)=12 m//s^(2)`
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