A stone is dropped from a height `h` . It hits the ground with a certain momentum `P` . If the same stone is dropped from a height `100%` more thanthe preyiious height, the momentum when it hits the ground will change by

Options

A. 2
B. 1
C. 0.68
D. 0.41

Answer

D

Explanation

`P=mv=msqrt(2ghr)ArrPprop sqrt(h)`
`(P_(f)-P_(i))/(P_(i))xx100%=(sqrt(h_(2))-sqrt(h_(1)))/(sqrt(h_1))xx100`
`[sqrt((h_(2))/(h_(1)))-1]xx100`
`={sqrt(((200)/(100)))-1}xx100`
`=(sqrt(2)-1)xx100`
`=0.44xx100=41%`