A stone falls freely under gravity. It covered distances `h_1, h_2` and `h_3` in the first `5` seconds. The next `5` seconds and the next `5` seconds respectively. The relation between `h_1, h_2` and `h_3` is :

Options

A. `h_(1)=h_(2)=h_(3)`
B. `h_(1)=2h_(2)=3h_(3)`
C. `h_(1)=(h_(2))/(3)=(h_(3))/(5)`
D. `h_(2)=3h_(1)` and `h_(3)=3h_(2)`

Answer

C

Explanation

`h_(1)=(1)/(2)g(5)^(2), h_(2)=(1)/(2)g(1-0)^(2)`
and `h_(3)=(1)/(2)g(15)^(2)`
`rArrh_(1)=(h_(2))/(3)=(h_(3))/(5)`