A ball whose kinetic energy is `E` , is projected at an angle of `45(@)` to the horizontal . The kinetic energy of the ball at the highest point of its flight will be

Options

A. E
B. `(E)/sqrt(2)`
C. `(E)/(2)`
D. zero

Answer

C

Explanation

`E=(1)/(2)mu^(2)`
and `E'=(1)/(2)mu^(2)cos^(2)45^(@)=Exx(1)/(2)=(E)/(2)`