For the system shown in the figure the cylinder on the left at L has a mass of 600 kg and a cross sectional area of `800cm^(2)` the piston on the right at S has cross sectional area `25cm^(2)` and negligible weight if the apparatus is filled with oil `(rho=0.75gm//cm^(3))` find the force F required to hold the system in equilibrium.

Answer

`37.5m`

Explanation

`(F)/(A_(1))+hrhog=(600g)/(A_(2)) implies (F+hrhogA_(1))/(A_(1)) = (600xxg)/(A_(2)) implies (F+hrhogA_(1))/(25) = (600g)/(32)`
`F + 8 xx 750 xx g xx 25 xx 10^(-4) = (1500g)/(8)`
`F = 187.5-150 " "implies F=37.5 N`