A cylindrical vessel open at the top is `20cm` high and `10 cm` in diameter. A circular hole of cross-sectional area `1cm^(2)` is cut at the centre of the bottom of the vessel. Water flows from a tube above it into the vessel at the rate of `10^(2)cm^(3)//s`. The height of water in the vessel under steady state is (Take `g=10m//s^(2))`.

Answer

5cm

Explanation

`{:(,V=a.v,implies,V=a sqrt(2gh)),(,100=1sqrt(2xx1000xxh),,),(,h=(10)/(2),,h=5cm):}`