Calculate the rate of flow of glycerine of density. `1.25xx10^(3) kg//m^(3)` through the conical section of a pipe. If the radii of its ends are `1.0m` and `0.04m` and the pressure drop across its length is `10N//m^(2)`.

Answer

`6.43xx10^(-4)m^(3)//s`

Explanation

`P_(1)+(1)/(2)rhov_(1)^(2)=P_(2)+(1)/(2)rhov_(2)^(2)`
`P_(1)-P_(2)=(1)/(2)rho(v_(2)^(2)-v_(1)^(2))`
`(2(P_(1)-P_(2)))/(rho)=V^(2)[(1)/(a_(2)^(2))-(1)/(a_(1)^(2))]`
` V=sqrt(((2(P_(1)-P_(2))//rho))/((1)/a_(2)^(2)-(1)/(a_(1)^(2))))=sqrt((((2xx10)/(1250)))/[[(1)/((pixx16xx10^(-4))^(2))-(1)/((pixx10^(-2))^(2))]))=6.43xx10^(-4)m^(3)//s`