A vertical communicating tube contains a liquid of density `rho`. If it moves with a horizontal acceleration `a`, pressure at `A` is equal to :

Answer

`(8h)/(7)`

Explanation

For equalibrium
`[hrhog+x(2rho)g]=P_(psuedo)+(h-x)rhog`
`hrhog+2xrhog=[(2h-x)2rho(g//2)+xrho(g//2)]+(h-x)rhog`
`hrhog+2xrhog=2hrhog-(xrhog)/(2)+xrhog+hrhog-xrhog`
`(7)/(2)xrhog=2hrhog`
`x=(4h)/(7)`
Difference in height `=2x=(8h)/(7)`