A cube with mass `m` completely wettable by water floats on the surface of water each side of the cube is `a` what is the distance `h` between the lower face of cube and the surface of the water if surafce tension is S. Take densities of water as `rho_(w)` take angle of contact is zero.

Answer

`h=(mg+4sa)/(rhowa^(2)g)`

Explanation

Weight `+` force due to surface tension = Buyonancy
`mg+4Sa=a^(2)hrho_(w)g`
`h=(mg+4Sa)/(a^(2)rho_(w)g)`